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See tutors like this. First change 20% to a decimal by moving the decimal point two places to the left. So, 20% = .20 = .2 (two-tenths) Now write .2 in fraction form. .2 = 2/10. Reduce 2/10 = 1/5. Upvote • 0 Downvote.
Quanny H. asked • 09/12/18 If 20% of the substance disappears in 10 years, what is its half-life? (Round your answer to two
Treena, if there was a 20% discount, then you paid 80% of the original price. Since we don't know the orginal price, we will assign it the variable x. Change 80% to a decimal. The equation would be:.8x = 276 To get the variable by itself, divide each side by .8..8x/.8 = 276/.8. x = 345. The original price of the suit was $345. Hope this is helpful.
So 125% = 125/100. That can be reduced to 5/4. To convert to a decimal, you can do long division, dividing 5 into 4. Or, you can realize 5/4 = 1 and 1/4, = 1.25. 125/100 is easier to see as a decimal. 125/100 = 1 and 25/100. "25 hundredths" is written down exactly as it is said 0.25, with the digit 5 in the hundredths place of the decimal.
Statistics Auestion Binomial Distribution. A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 17 randomly selected pens yields no more than two defective pens. (a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)
The problem 20% of 10 is a multiplication problem because you want something of something. Note: 20% = 0.20 = 20/100 = 1/5. 0.20 x 10 = 2 revisit the rule for multiplying decimal or. 20/ 100 x 10 / 1 = 200/100 = 2 revisit the rule for multiplying fractions or. diagram 10 divided into 5 parts which have 2 in each equal part.
To find amount that is 20% greater, take amount from 2 years ago, 10.2 inches, and add 20% of 10.2 inches: 10.2 + 20% of 10.2 20% is 0.20 in decimal and "of" translates to multiplication, so
Here's the long way: solve for k first, given the half life of 7310 yrs. Assume A 0 = 1gm. A/A 0 = 1/2 = 1e 7310k Take the ln of both sides: ln(0.5) = 7310k
I assume that the probability of defective products is 20%. I ignored the statement: "5% defective products" Number of de fective parts = .2 * 700 = 140. Number of good parts = .8 * 700 = 560. Cost to produce 700 parts = 700 * 36 = $25,200. Cost to repair 560 parts = 140 * 14 = $1,960. Total expected cost = $27,160
For your problem, after 3 days, 58% of the original sample remains which is information that will help us find the decay rate. You can choose anything you want for the initial amount, as long as your final amount represents 58% of that amount. It is easiest, since we are dealing with percentages, to use 100 as the initial amount and then 58 ...