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30. You need the random python module which is part of your standard library. Use the code... from random import randint. num1= randint(0,9) This will set the variable num1 to a random number between 0 and 9 inclusive. answered Apr 1, 2021 at 10:09. SamTheProgrammer.
@RajeshSwarnkar random.random() * 2*math.pi, as the doc says the random function "Return[s] the next random floating point number in the range 0.0 <= X < 1.0" – Magnus Teekivi Commented Feb 15, 2023 at 9:23
random.random() Return the next random floating point number in the range [0.0, 1.0). But if your inclusion of the numpy tag is intentional, you can generate many random floats in that range with one call using a np.random function.
NumPy solution: numpy.random.choice. For this question, it works the same as the accepted answer (import random; random.choice()), but I added it because the programmer may have imported NumPy already (like me)
To avoid wasting time looping for useful random number, I suggest you create a list from 0 to 9 using for loop [0,1,....9,]. then you shuffle this list once randomly. [ 4,8,0,....1] to get a random number, just "poll" the first number from this list each time you want a random number (which will not exist in the list the next time read).
So to get a random 3-digit number: from random import randint, randrange randint(100, 999) # randint is inclusive at both ends randrange(100, 1000) # randrange is exclusive at the stop * Assuming you really meant three digits, rather than "up to three digits".
return (string.letters+string.digits) keylist = [random.choice(base_str()) for i in range(KEY_LEN)] return ("".join(keylist)) You can get random strings like this: 1. With Python3, it would be string.ascii_letters 2. You can save the list comprehension by using keylist = random.choices(base_str(), k=KEY_LEN) 3.
In Python 2 (and Python 3) you can do: number = 1. print("%02d" % (number,)) Basically % is like printf or sprintf (see docs). For Python 3.+, the same behavior can also be achieved with format: number = 1. print("{:02d}".format(number)) For Python 3.6+ the same behavior can be achieved with f-strings: number = 1.
I am a bit confused about how the random.random() function works in python. The docs say that it 'Return the next random floating point number in the range [0.0, 1.0)'. I understand that pseudo-random number generators work by performing some operation on a value. Generally this value is the previous number generated by the generator.
97. You could use random.sample to generate the list with one call: import random. my_randoms = random.sample(range(100), 10) That generates numbers in the (inclusive) range from 0 to 99. If you want 1 to 100, you could use this (thanks to @martineau for pointing out my convoluted solution):