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  2. How to use DATEDIFF to return year, month and day?

    stackoverflow.com/questions/1541570

    6. Create this function, it will give exact date difference like year months days. Create function get_Exact_Date_diff(@date smalldatetime,@date2 smalldatetime) returns varchar(50) as. begin. declare @date3 smalldatetime. Declare @month int,@year int,@day int. if @date>@date2.

  3. This is the lubridate approach I would take: interval (dob, today) / years (1) Yields the answer of 32 years. Note that the function will complain that it cannot express the remainder of the fraction of the year. This is because year is not a fixed concept, i.e. 366 in leap years and 365 in non-leap years. You can get an answer with more detail ...

  4. c# - Format A TimeSpan With Years - Stack Overflow

    stackoverflow.com/questions/15957984

    If the total days are less than 1, I would like to omit the day section. If either years or days are 0, they should say "day/year", rather than "days/years" respectively. Examples: 2.2 years: "2 years 73 days" 1.002738 years: "1 year 1 day" 0.2 years: "73 days" 2 years: "2 years" What I have works, but it is long:

  5. 23. the simplest answer is, assuming the need is to add 1 day to the current date: var currentDate = new Date(); var numberOfDayToAdd = 1; currentDate.setDate(currentDate.getDate() + numberOfDayToAdd ); To explain to you, line by line, what this code does: Create the current date variable named currentDate.

  6. How to convert number of days to years,months and days

    stackoverflow.com/questions/19632069

    Based on your comments and the following conditions. 1 year = 365 days. 1 month = 30 days. Then the following code would do the job. DateTime startDate = new DateTime(2010, 1, 1); DateTime endDate = new DateTime(2013, 1, 10); var totalDays = (endDate - startDate).TotalDays;

  7. If you need to convert total days to years, months, and days (within in month), use the following code: The output in three separate columns is: The following code "combines" the results into one column: CAST(FLOOR(DATEDIFF(DD, [cA].[Date2], GETDATE()) % 30.4375) AS varchar) + ' Days' AS 'Duration'. The output in one column is:

  8. Calculate exact date difference in years using SQL

    stackoverflow.com/questions/23145404

    You'll get a more accurate result if you compute the difference between the two dates in days and divide by the mean length of a calendar year in days over a 400 year span (365.2425): datediff(day,{start-date},{end-date},) / 365.2425 For instance, select datediff(day,'1 Jan 2000' ,'18 April 2014') / 365.2425

  9. How do I convert days into years and months in python?

    stackoverflow.com/questions/32083726

    Using dateutil.relativedelta.relativedelta is very efficient here: Except for using .months or .days.. because rdelta.months gives you the remaining months after using full years, it doesn't give you the actual difference in months.

  10. SELECT DATEDIFF('2012-04-30', '2009-05-24') `total_days`; return 1072 days, which is roughly 2 Years, 11 Months, 12 Days. Please do not answer with PHP code, I already try it. Here is the code. The function below uses PHP >= 5.3 functions and convert days to years, months and days.

  11. Not only does strtotime() fail in 20 years, it's unusable right now. The OP specified Dates, not Time. Dates can be quite old.